25度时,已知溶解度S g,摩尔质量M g/mol,密度d g/cm^3,求物质的量浓度...答:所以溶解的溶质质量 = 1000dV/(100+S) * S = 1000SdV/(100+S)所以溶解的溶质物质的量 = [1000SdV/(100+S)]/M = 1000SdV/[M(100+S)]所以物质的量浓度 = {1000SdV/[M(100+S)]}/V = 1000Sd/[M(100+S)],8,25度时,已知溶解度S g,摩尔质量M g/mol,密度d g/cm^3,求物质...