设计一个算法,求一维数组float a[n]中所有元素之和,写出相应C程序...答:int i = 0;//...for( i = 0,result=0; i < n; i++){ result += a[i];} include <stdio.h> int main(){ int n = 10;int i = 0;float a[10] = {1,2,3.4,5.5,2.3,1.2,1.6,7,8,12.12};float result = 0;for (i = 0, result = 0; i < n; i++)...
c语言求二维数组中所有元素的和答:int main(void){ int ar[3][3]= { {1,2,3},{4,5,6},{7,8,9} };int num;int i,j;int k = 0,sum=0;int (*ptr)[3];ptr = ar;num = sizeof(ar) / sizeof(ar[0]);printf("num = %d\n",num);printf("%d\n",*(*(ptr +0) + 1));for(i = 0; i < 3...