c语言0~9十个数排列组合,每次运行得到不同的排列组合,例如0.2.1.5.6.3...答:include #include #include #include #include using namespace std;int f[4]={0,1,2,3};char ch[4][10]={"a2b8","5a8f","b9ec","5c2f"};int main(){ int i,j,k; for(i=0;i<24;i++)//共4!个排列 { for(j=0;j<4;j++) printf("%s",ch[f[j]]...
用C语言中的数组的知识输出0到9,很基础的。给个详细过程,谢谢答:int i,a[10]; //定义数组,有10个元素a[0],a[1],...,a[9]for(i=0;i<10;i++)a[i]=i; //给a[0],a[1],...,a[9]十个元素分别赋值为0,1,..,9 for(i=0;i<10;i++)printf("%d ",a[i]);//输出十个数组元素的值 return 0;} ...
从0到9,任意选取5个数,输出这五个数的所有排列(用C语言编程)答:include<stdio.h> include include<stdlib.h> int a[10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};int b[5], rank[5];bool used[10] = {false};bool p_used[5] = {false};void Permutation(int deep);void main(){ int i = 0, j = 0, k = 0, temp;srand((unsigned...