c语言 编程 求方程ax2+bx+c=0的根,用三个函数分别求当b2-4ac大于0...答:else if (d==0)y(a,b,c);else printf("无解");} void x(float a,float b,float c ,float d){ float x1,x2;x1=(-b+sqrt(d))/(2.0*a);x2=(-b-sqrt(d))/(2.0*a);printf("x1=%.3f\nx2=%.3f\n",x1,x2);} void y(float a,float b,float c){ float x1;x1=...
C语言程序求方程ax^2+bx+c=0的根,用3个函数分别求当b^2-4ac大于0,等于...答:b-d)/a);}void _f(double a,double b,double d){d=sqrt(-d),a=-b/a/2,b=d/a/2; printf("x1 = %f%+fi\nx2 = %f%+fi\n",a,b,a,-b);}void f0(double a,double b){printf("x1=x2 = %f\n",-b/a/2);}int main(int argv,char *argc[]){double a,b,c,d;...
编写程序求ax2+bx+c=0的根答:x1=(-b)/(2*a);x2=sqrt(-disc)/(2*a);printf("有两个虚根:x1=%5.2f+%5.2fi,x2=%5.2f-%5.2fi\n",x1,x2,x1,x2);} //-- void main(){ float a,b,c,disc;printf("输入方程的系数:");scanf("%f%f%f",&a,&b,&c);disc=b*b-4*a*c;if(disc>0)greater(a,...