C语言程序,急答:-1};int dy[]={-1,1,0,0,1,-1,1,-1};int n,m,sx,sy,ex,ey;int mp[55][55],visit[55][55];struct node{ int x,y,step;}q[55 * 55];int check(int x,int y){ if(x < 1 || x > n) return 0;
C语言程序设计 源代码+注释答:char A[64][64]= {"..###","#...","#.#.#","#.#.#","#.#.."};//迷宫,A,R,C这里预设,实际请改成输入 int M[64][64] = {0}, //标记走过的点 R = 5, C = 5;//判断点(x,y)是否可达 bool pass(int x, int y){ return x>=0 && x<=R && y>=0 &&...
求C语言汉诺塔非递归算法答:if (top >= 0) { /* 向右走一步 */ move(p[top].x, p[top].n, p[top].z);top--;push(p, top, p[top+1].y, p[top+1].x, p[top+1].z, p[top+1].n);top++;} } }int main(void){ int i;printf("reverse program:n");hanoi(3, 'x', 'y', 'z');printf...