用c语言编写四则运算,急呀!越简单越好答:用纯粹的C语言实现,代码如下:include<stdio.h>int main(){ double a,b; scanf("%lf%lf", &a, &b); printf("a+b=%lf, a-b=%lf, a*b=%lf", a+b, a-b, a*b); if(b==0) printf(", error!\n"); else printf(", a/b=%lf\n", a/b); ...
用c语言编写四则运算,急呀!越简单越好答:include <stdio.h> void main(){ int a,b;char op;scanf("%d%c%d",&a,&op,&b);switch(op){ case '-':printf("%d%c%d=%d\n",a,op,b,a-b);break;case '+':printf("%d%c%d=%d\n",a,op,b,a+b);break;case '/':if(b==0)printf("error\n");else printf("%d%c%d...
C语言进行四则运算的计算器答:scanf("%d%c%d",&num1,&op,&num2);printf("=%d\n",process(num1,op,num2));//标记 printf("\n\n\n");char mymy[8]={37,28,14,6,29,8,42,25};char mymystr[]={-21,-50,-69,-62,-52,-13,-19,-14,-25,-9,93,86,43,61,18,77,17,-65,-94,-78,-17,-73,-...