C语言编写一个求两点距离公式,求三角形面积答:include<stdio.h>#include<math.h>float b(float x,float y,float m,float n){ float d; d=sqrt((x-m)*(x-m)+(y-n)*(y-n)); return(d);}int main(){ float x1,x2,x3,y1,y2,y3,d1,d2,d3,s,q; scanf("(%f,%f)(%f,%f)(%f,%f)",&x1,&y1,&x2,&y2,&x3...
c语言要求输入三角形三条边,输出面积,比如输入345,输出6.0,输入123...答:include <stdio.h> include <math.h> void main(){ float a,b,c,p,s;printf("请输入三角形三边长:");scanf("%f%f%f",&a,&b,&c);p = (a+b+c)/2;s = sqrt(p*(p-a)*(p-b)*(p-c));printf("三角形面积为:%.1f\n",s);} include <stdio.h>//添加了判断三边能否...