js用for对数组的操作,大神进答:var data = [{"xvalue":"美国","yvalue":"方法","value":"42"},{"xvalue":"美国","yvalue":"计算机","value":"92"},{"xvalue":"山东","yvalue":"一种","value":"100"},{"xvalue":"山东","yvalue"
JS数组5个选3个,5个选2个怎么写答:其他按从小到大顺序)//从3,5,9,6,11里边取3个,有C(5,3)=5*4*3/(3*2*1)=10中取法;//再从剩下的(11-3)=8个数里边取两个,有C(8,2)=8*7/(2*1)=28种取法。//共有10*28=280种排列方式,去掉里边[3,5,9,6,11]的排列(C(5,3)*1=10种),所以最终结果为280-10=...
...到json数组里,判断是否存在,并获得json数组的值答:var param = [{id:1,value:[1,3,5]},{id:1,value:[1,2,3]}];var check = [1,3,5];var judge = function (check, param) { var isExisted = false; $.each(param, function (i, n){ if (n.value.sort().join(",") == check.sort().join(",")) { is...
求教!js二维数组中,如何把具有相同种类name的值筛选出来,组成三维数组...答:var college = [ [{name:'北京'},{city:'西安'}], [{name:'上海'},{city:'包头'}], [{name:'广州'},{city:'福州'}], [{name:'北京'},{city:'广州'}], [{name:'广州'},{city:'太原'}], [{name:'上海'},{city:'昆明'}]];var result = [...