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k70买12+256还是16+256
...C.1/32 D.1/
16
行测 6, 13, 31, 57, 131 A
256
B212 C181 D173...
答:
此为等比数列 ,下一项1/4x =8 x=1/32 所以答案为c,1/32 行测 6, 13, 31, 57, 131 A
256
B212 C181 D173 131=11^2+10 57=7^2+8 31=5^2+6 13=3^2+4 6=2^2+2 可见是质数的平方加上一个等比数列 下一项为:13^2
+12
=169+12=181 所以答案为c,181 ...
3/4+3/
16+
3/64+3/
256+
3/1024+3/4096=( )
答:
3/4+3/
16+
3/64+3/
256+
3/1024+3/4096 =3/4*[1-(1/4)^6]/(1-1/4)=4095/4096 或者 3/4+3/16+3/64+3/256+3/1024+3/4096 =3072/4096+768/4096+192/4096+48/4096
+12
/4096+3/4096 =4095/4096
3/4+3/
16+
3/64+3/
256+
3/1024+3/4096=
答:
3/4+3/
16+
3/64+3/
256+
3/1024+3/4096 =3/4*[1-(1/4)^6]/(1-1/4)=4095/4096 或者 3/4+3/16+3/64+3/256+3/1024+3/4096 =3072/4096+768/4096+192/4096+48/4096
+12
/4096+3/4096 =4095/4096
1-1/2+1/4-1/8+1/
16
-1/32+1/64-1/128+1/
256
-1/512+1/1024-1/2048
答:
1-1/2+1/4-1/8+1/
16
-1/32+1/64-1/128+1/
256
-1/512+1/1024-1/2048=1-(-1/2)^
12
/(1+1/2)=2/3[1-(1/2)^12]=(2/3)*(4095)4096 =4095/3*2048 =1365/2048
根号(
12
^2+t^2)=
16
-t
答:
两边平方,得 144+t^2=
256
-32t+t^2 32t=112 t=3.5
脱式计算.12×28+567÷21336÷(
12+
750÷25)560-912÷24×5592÷(71-34...
答:
(1)12×28+567÷21,=336+27,=363;(2)336÷(
12+
750÷25),=336÷(12+30),=336÷42,=8;(3)560-912÷24×5,=560-38×5,=560-190,=370;(4)592÷(71-34)×
16
,=592÷37×16,=16×16,=
256
.
1\2+3\4+7\8+15\
16+
31\32+...+127\128+255\
256
写出主要过程
答:
1\2+3\4+7\8+15\
16+
31\32+...+127\128+255\
256
=8-(1/2+1/4+1/8+1/16+1/32+……+1/128+1/256)=8-(1-1/256)=7+1/256 =7又1/256
棣栭〉
<涓婁竴椤
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