编写一个函数,实现对任何小于n个整数能够按从大到小的顺序输出,n和n...答:include "stdio.h"void sort(const int, int*);int main(int argc, char** argv) {int array[] = {5, 34, 54, 2, 54, 51, 543, 2};int i = 0;int arraySize = sizeof(array)/sizeof(array[0]);sort(arraySize, array);for (i = 0; i < arraySize; ++ i) {printf("...
...sort(int*p,int n),在主函数中两次调用,对3,9,答:include<stdio.h> void sort(int *p,int n);int main(){ int i,arr1[6]={3,9,2,8,6,1},arr2[10]={11,5,18,7,2,15,4,13,9,3};sort(arr1,6);sort(arr2,10);printf("排序的结果:\n");for(i=0;i<6;i++)printf("%3d",arr1[i]);printf("\n");for(i=0;i<...