如图,二重积分,先对x积分,原函数y前面怎么不用乘以x呢??答:说明:^——表示次方 ∫(0,y^2)√(y^2-x)dx =-∫(0,y^2)√(y^2-x)d(y^2-x)=-2/3(y^2-x)^(3/2)|(0,y^2)=-2/3[(y^2-y^2)^(3/2)-(y^2-0)]=2/3y^2 ∫(0,1)dy∫(0,y^2)√(y^2-x)dx =∫(0,1)(2/3y^2)dy =(2/3)(1/3)y^3|(0,1)=...
ax×bx的积分再乘以cx×dx的积分减去x×x的积分乘以dx×dx的积分能不...答:f(t)dt,显然g(x)在[ a,b ]连续 g(a)=-∫(a~b)f(t)dt,g(b)=∫(a~b)f(t)dt,(1)若∫(a~b)f(t)dt=0,则可取c=a或c=b (2)若∫(a~b)f(t)dt≠0,则g(a)g(b)<0,又g(x)在[ a,b ]连续,于是必定存在c∈(a,b),使得g(c)=0 即∫(a~c)f(t)dt=∫(c~b)...