编写程序,其功能是把数组a中的奇数按原来的先后顺序放在原数组...答://我来写一段代码 #include <stdio.h>int main(){int a[] = {2,3,1,23,4,5,34,54,34,54,44,342,90,89,78,79};int i ,j=15; //15是数组的最大的下标,等于数组个数-1while(1){while(a[j] % 2 && j>=0) j--;i = j-1;while(a[i] % 2 == 0 && i>=0) i...
...的20个元素保存在10×2的二维数组中,且偶数与奇数分别存储在两列上...答:我是假定20个元素能保证 一半是偶数,一半是奇数 include <stdio.h> int main(){ int a[20] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19};int b[10][2];int i,j,k;j = 0;k = 0;for(i=0; i<20; i++){ if(a[i]%2==0) //如果是偶数,存放...