分别求出数组中所有奇数之和以及所有偶数之和。答:代码: #include <stdio.h>#define N 10void fun(int *a,int n,int *odd,int *even){ int i;even=0;odd=0;for(i=0;i<n;i++){ if(a[i]%2==0)even=*even+a[i];else odd=*odd+a[i];} }void main(){ int a[N]={1,10,2,3,19,6},i,n=6,odd,even; pr...
给定一个数组求奇数和偶数之和答:include<stdio.h> int main(){ int i,n=10,a[10]={1,2,3,4,5,6,7,8,9,10},s1=0,s2=0;for(i=0; i<n; i++)if(a[i]%2)s1+=a[i];else s2+=a[i];printf("奇数之和=%d\n偶数之和=%d\n",s1,s2);return 0;} ...