求y=cos^2x^2的微分。详细步骤，谢谢。

Question

如题所述

Answer 1

y= (cos(x^2))^2
dy = 2(cos(x^2) d(cos(x^2))
=2(cos(x^2) (-sin(x^2)) d(x^2)
= -4xcos(x^2) .sin(x^2) dx本回答被网友采纳

Answer 2

y=cos²x²
y'=-2cosx²sinx²2x
=-2xsin2x²
dy=-2xsin2x²dx

Answer 3

2*cos(x^2)*(-sin(x^2))*(2x)
=-4*x*cos(x^2)*sin(x^2)