1-tan22.5度的平方/tan22.5度=？

Question

计算过程是什么，谢谢！

Answer 1

1-tan22.5度的平方/tan22.5度
=【（1-tan22.5度的平方）*2】/【tan22.5度*2】
=2本回答被提问者采纳

Answer 2

(1-tan^2(22.5度)) / (tan(22.5度))

= (1 - sin^2(22.5度)/cos^2(22.5度)) / (sin(22.5度)/cos(22.5度))

= (cos(22.5度) - sin^2(22.5度)/cos(22.5度)) / (sin(22.5度))

= (cos^2(22.5度) - sin^2(22.5度)) / (sin(22.5度)cos(22.5度))

= (cos(2*22.5度)) / (sin(2*22.5度)/2)

= (cos(45度)) / (sin(45度)/2)

= 1/(1/2)

= 2

Answer 3

设原式=x
1
=tan45
=(2tan22.5)/(1-(tan22.5)^2)
=2/x
所以x=2