编写程序，统计课程编号为1001、1002、2001和3001的平均成绩并输出。学生成绩表如图2.11所示

Question

【每个课程编号的成绩用数组存储，读取时循环操作】

Answer 1

public class xscj2
{
public static double avg (double n[]){
double count = 0;
for(int i=0; i<n.length; i++){
count += n[i];
}
return count/n.length;
}
public static void main(String[] args)
{
double a2;
double b2;
double c2;
double d2;
double a[]={90,85,66,51,69,78,88,94};
double b[]={68,88,81,90,65,74,64,46};
double c[]={68,90,85,88,68,70};
double d[]={60};
a2=avg (a);
b2=avg (b);
c2=avg (c);
d2=avg (d);
}
public pd(double x[]){

}

}