C++语言 输入n个整数求平均值

Question

注意是C++
Sample Input

2
18
17

Sample Output

17.50

Answer 1

VC++ 6.0的程序如下，如果在.NET下运行，头文件需要改动，并加上域名的说明语句；
#include<iostream.h>

void main()
{
int n,i,num,total;
n=num=total=0;
float ave;
cout<<"enter the number of numbernal: "<<endl;
cin>>n;
for(i=0;i<n;i++)
{
cout<<"enter the numbernal: "<<endl;
cin>>num;
total=total+num;
}
ave=total/n;
cout<<"the average of numbernal is: "<<ave<<endl;
}

Answer 2

#include "stdio.h"
#include "conio.h"
void main()
{
int n;
int num;
int sum;
int i;
sum = 0;
scanf("%d", &n);
for(i=0; i<n; i++)
{
scanf("%d", &num);
sum += num;
}
printf("%.2f", (float)sum/n);
getch();
return;
}本回答被提问者采纳

Answer 3

#include<iostream>
using namespace std;
int main()
{
int n,i,j,s=0;
cin>>n;
for(i=1;i<=n;i++)
{
cin>>j;
s+=j
}
cout<<s*1.0/n;//也可以这样：cout<<(double)s/n;
return 0;
}