c语言编程填空题:输出100到1000之间既是奇数且能被13整出的数,并输出他们的和。

Question

#include<stdio.h>
int main()
{
int i,(____);
for(i=100;i(______)1000;i++)
if(i%2(_______)0 && (_______)==0)
{
sum=sum+i;
print("%d",(______) );
}
print("\n The sum is:%d\n",sum);
return 0;
}

Answer 1

#include<stdio.h>
int main()
{
int i, sum=0 ;
for(i=100;i <=1000 ; i++)
if( ( ( i % 2 ) != 0 ) && ( ( i%13)==0 ) )
{
sum=sum+i;
print("%d", sum );
}
print("\n The sum is:%d\n",sum);
return 0;
}本回答被提问者采纳

Answer 2

sum
<=
!= i%13
sum