第1个回答 2016-12-09
#include <iostream>
using namespace std;
#define N 10
void array_input(int array[], int n){
for(int i=0; i<n; i++) cin>>array[i];
}
int square_sum(int array[], int n){
int sum = 0;
for(int i=0; i<n; i++) {
sum += array[i]*array[i];
}
return sum;
}
void main () {
int array[N] = {0};
cout<<"请输入";
cout<<N;
cout<<"个正整数:";
array_input(array, N);
int sum = square_sum(array, N);
cout<<sum;
getchar();
getchar();
}本回答被提问者和网友采纳