定义了两个unsigned char类型的变量a,b；怎样将这两个变量整合成一个float类型的变量

Question

a是整数部分，b是小数部分，即：a.b

Answer 1

#include<iostream>
using namespace std;
int main()
{
unsigned char a = 8;
unsigned char b = 66;
float c;
float temp = b;
while( temp > 1 )//循环条件
{
temp = temp/10;//将b变成小数形式
}
c = a + temp;
cout<< c <<endl;
return 0;
}

Answer 2

#include<stdio.h>
#include<math.h>
main()
{unsigned char a,b;
float f;
int c,d;
scanf("%c%c",&a,&b);
d=b-48;
for(c=0;d>0;d/=10)
c++;
f=a-48+(b-48)/pow(10,c-1);
printf("%f\n",f);
}
由于

Answer 3

unsigned char a = 2;
unsigned char b = 155;

int i = 0;
float temp = b;

for(;(temp=temp/10)>1;);

float c = a + temp;本回答被提问者采纳

Answer 4

看看这个帖子吧：

Answer 5

1楼的哥们给力