解:(1)溴乙烷发生消去反应生成乙烯,该反应为CH
3CH
2Br
CH
2=CH
2↑+HBr,
故答案为:CH
3CH
2Br
CH
2=CH
2↑+HBr;消去反应;
(2)甲苯发生取代反应生成TNT,该反应为
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/2f738bd4b31c8701a9358f54247f9e2f0608ff84?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
故答案为:
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/2f738bd4b31c8701a9358f54247f9e2f0608ff84?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
;取代反应;
(3)发生银镜反应生成乙酸铵、水、Ag、氨气,该反应为CH
3CHO+2Ag(NH
3)
2OH
CH
3COHNH
4+H
2O+2Ag+3NH
3↑,
故答案为:CH
3CHO+2Ag(NH
3)
2OH
CH
3COHNH
4+H
2O+2Ag+3NH
3↑;银镜反应.