根号x的导数怎么求

Question

怎么求

Answer 1

(x^n)'=n*x^(n-1)
根号X等于X的二份之一次方
令n=1/2代入
(x^1/2)'=（1/2）*x^(-1/2)

Answer 2

y=√x
=x^1/2
y'=1/2(x^(1/2-1)
=1/2x^-1/2
=1/√x

Answer 3

½
y=√x=x
－½
y'=½(x) ＝1／2√x本回答被提问者和网友采纳