一元二次方程含参问题解法

Question

如题所述

Answer 1

Let L =含(secr)*n dar
=含(secz)*(n-2) * sec2r dr
=日(secr)(n-2) d(tanx)
= (tanz)(secz)(n-2) -£tanz d(secz)(n-2)=(sin.x/cosaz)(secz)^(n-1) * (1/secz) -(n-2)] t anar * (seca)*(n·3) * (secztanz) dr
=(sin.x/cosz)(secz)^(n-1) * cosz - (n-2)[ tan?z
*(secz)(n-2) dar
=(sinz)(secz)(n-1)-(n-2)[(seczx-1)(secz)~(n-
2) dar
=(sinx)(secz)~(n-1) - (n-2)[L -目(secz)~(n-2)]
d.ax
[1 +(n-2)]L=(sinz)(secz)(n-1) +(n-2)[(sec
2)^(n-2) dar
(n-1)L =(sinz)(secz)*(w-1) +(n-2)[(secz)~(n-
2) dar
L = [1/(n-1)](sinz)(secr)(n-1) + [(n-2)/(n-1)]