(a+1)^-1/2=[1/(a+1)]^1/2 a+1>=0 a>=-1
(3-2a)^-1/2=[1/(3-2a)]^1/2 3-2a>=0 a<=3/2
è¿ä¸¤èå´é½æ¯å 为1/2æ¬¡æ¹ 1/2次æ¹å°±æ¯å¼æ¾ å ä¸ºæ ¹å·ä¸çæ°>=0
åæ1/(a+1) æ以a+1â 0 1/(3-2a) æ以(3-2a)â 0
综åå¾å°-1<a<3/2
(a+1)^-1/2<(3-2a)^-1/2 ä¹å°±æ¯
[1/(a+1)]^1/2<[1/(3-2a)]^1/2
æ以1/(a+1)<1/(3-2a) a>2/3
æ以2/3<a<3/2
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