定义一个有20个元素的整型数组，分别求出下标为奇数和偶数的元素的平均值。用c语言解答

Question

如题所述

Answer 1

#include<stdio.h> main(){
int n[20]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
float v1,v2;
int i,n1,n2;
v1=v2=n1=n2=0;
for(i=0;i<20;i++)
{
if(i%2==0)v1+=n[i],n1++;
else v2+=n[i],n2++;
}
v1/=n1;
v2/=n2;
printf("下标为偶数的元素平均值:%lf,下标为奇数平均:%lf\n",v1,v2);
getch();
}

Answer 2

#include<stdio.h>main()
{
int n[20]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20};
double v1,v2;
int n1,n2,i;
v1=v2=n1=n2=0;
for(i=0;i<20;i++)
if(n[i]%2==0)v1+=n[i],n1++;
else v2+=n[i],n2++;
v1/=n1;
v2/=n2;
printf("偶数平均:%lf,奇数平均:%lf\n",v1,v2);
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