c语言:输入6个字符，用冒泡排序法将这些字符按ASCII码值从大到小输出。

Question

如题所述

Answer 1

输入6个字符,例如：
enter char 1: 8
enter char 2: d
enter char 3: h
enter char 4: K
enter char 5: k
enter char 6: &

按ASCII码值从大到小输出
k h d K 8 &

程序如下：

#include <stdio.h>
void main()
{
unsigned char a[6];
int i,j,tmp;
for(i=0;i<6;i++)
{
printf("enter char %d: ", i+1);
fscanf(stdin,"%c",&a[i]); fflush(stdin);
};

for (i=0;i<5;i++)
for (j=i+1;j<6;j++)
if ( a[j]>a[i] ) {
tmp = a[j]; a[j]=a[i]; a[i]=tmp;
};

for (i=0;i<6;i++) printf("%c ",a[i]);

getch();
}

Answer 2

输入6个字符,例如：
enter
char
1:
8
enter
char
2:
d
enter
char
3:
h
enter
char
4:
K
enter
char
5:
k
enter
char
6:
&
按ASCII码值从大到小输出
k
h
d
K
8
&
程序如下：
#include
<stdio.h>
void
main()
{
unsigned
char
a[6];
int
i,j,tmp;
for(i=0;i<6;i++)
{
printf("enter
char
%d:
",
i+1);
fscanf(stdin,"%c",&a[i]);
fflush(stdin);
};
for
(i=0;i<5;i++)
for
(j=i+1;j<6;j++)
if
(
a[j]>a[i]
)
{
tmp
=
a[j];
a[j]=a[i];
a[i]=tmp;
};
for
(i=0;i<6;i++)
printf("%c
",a[i]);
getch();
}