说明代数式[(x-y)的平方 -(x+y)(x-y)]除以(-25y)+y的值与y的值无关

Question

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Answer 1

[(x-y)的平方 -(x+y)(x-y)]除以(-2y)+y
=(x-y)(x-y-x-y)÷(-2y)+y
=(x-y)(-2y)÷(-2y)+y
=x-y+y
=x

化简后,代数式[(x-y)的平方 -(x+y)(x-y)]除以(-2y)+y的值不含字母y,
所以与y的值无关

题目打错了,应该是 除以(-2y)追问

呵呵 是打错了 谢谢您