2011ä¸èæ»å¤ä¹ æ°å¦ææè¿å
³è®ç»ï¼å¾è¡å®çä¸ã填空é¢1.ä¸ä¸ªç´è§ä¸è§å½¢çä¸è¾¹é¿æ¯ä¸å¤§äº10çä¸ä¸ªè¿ç»å¶æ°,åå®çå¨é¿æ¯________________.çæ¡ï¼24æ示ï¼æ ¹æ®å¾è¡å®çï¼ä¸¤ç´è§è¾¹çå¹³æ¹åçäºæè¾¹çå¹³æ¹ï¼è®¾å
¶ä¸ä¸æ¡ç´è§è¾¹ä¸ºxï¼å¦ä¸¤æ¡åå«ä¸º(x-2)ï¼(x+2),åæ(x-2)2+x2=(x+2)2ï¼è§£å¾x=0æx=8ï¼x=0ä¸åé¢æèå»ï¼æ以ä¸è¾¹é¿ä¸º6ã8ã10ï¼å¨é¿ä¸º24.2.å¨â³ABCä¸,è¥AB=17,AC=8,BC=15,åæ ¹æ®______________å¯ç¥â ACB=_______________.çæ¡ï¼å¾è¡å®çéå®ç 90°æ示ï¼å¾è¡å®çéå®çæ¯å¤å®ä¸ä¸ªè§æ¯ç´è§çéè¦æ¹æ³ï¼AC2+BC2=82+152=289=172=AB2ï¼æ ¹æ®å¾è¡å®ççéå®ç说æABç对è§æ¯90度.3.ä¸åº§åç´äºä¸¤å²¸çæ¡¥é¿15ç±³,ä¸èå°è¹èªæ¡¥å头åºå,åæ£åæ¹å驶å»,å æ°´æµåå ,å°è¾¾å岸å,åç°å·²å离桥å头9ç±³,åå°è¹å®é
è¡é©¶äº______________ç±³.çæ¡ï¼3 æ示ï¼æ¡¥é¿ãå离桥å头çè·ç¦»ãå®é
è¡é©¶çè·¯ç¨ææä¸ä¸ªç´è§ä¸è§å½¢ï¼å©ç¨å¾è¡å®çï¼å¯å¾å®é
è¡é©¶çè·¯ç¨çå¹³æ¹=152+92=306ï¼æ以å®é
è¡é©¶äº3 ç±³.4.è¥ä¸è§å½¢ä¸ç¸çç两边é¿ä¸º10 cm,第ä¸è¾¹é¿ä¸º16 cm,å第ä¸è¾¹ä¸çé«ä¸º_____________cm.çæ¡ï¼6æ示ï¼çè
°ä¸è§å½¢ä¸çº¿åä¸ï¼åºè¾¹ä¸çé«ä¹æ¯åºè¾¹çä¸çº¿ï¼æ以åºè¾¹çä¸å为8ï¼åé«ä¸º = =6.5.å¦å¾8-41,ç©å½¢ABCD,AB=5 cm,AC=13 cm,åè¿ä¸ªç©å½¢çé¢ç§¯ä¸º______________cm2.å¾8-41çæ¡ï¼60æ示ï¼æ ¹æ®å¾è¡å®çæ±åºBCçé¿ï¼BC2=132-52=144ï¼åBC=12ï¼é¢ç§¯ä¸º5Ã12=60.6.çè¾¹ä¸è§å½¢çè¾¹é¿ä¸º4,åå
¶é¢ç§¯ä¸º_______________.çæ¡ï¼4 æ示ï¼æ ¹æ®å¾è¡å®çæ±åºé«ä¸º =2 ï¼é¢ç§¯ä¸ºåºÃé«Ã =4à =4 .7.å¦å¾8-42,å¨é«3ç±³,å¡é¢çº¿æ®µè·ç¦»AB为5ç±³ç楼梯表é¢éºå°æ¯¯,åå°æ¯¯é¿åº¦è³å°é____________ç±³.å¾8-42çæ¡ï¼7æ示ï¼ç±å¾è¡å®çæ±åºå¦ä¸ç´è§è¾¹ä¸º4ï¼å°æ¥¼æ¢¯è¡¨é¢åä¸åå³å¹³ç§»ï¼åå°æ¯¯çæ»é¿=两ç´è§è¾¹çå=3+4=7.8.è¥ +|a-12|+(b-5)2=0,å以aãbãc为ä¸è¾¹çä¸è§å½¢æ¯______________ä¸è§å½¢.çæ¡ï¼ç´è§æ示ï¼æ»¡è¶³a2+b2=c2.äºãéæ©é¢9.ä¸åæ¯å¾è¡æ°çä¸ç»æ¯A.4,5,6 B.5,7,12 C.12,13,15 D.21,28,35çæ¡ï¼Dæ示ï¼æ»¡è¶³a2+b2=c2çæ£æ´æ°æ¯å¾è¡æ°ï¼åªæ212+282=352ï¼æ以éD.10.ä¸å说æ³ä¸æ£ç¡®çæ¯A.ä¸ä¸ªè§ç度æ°ä¹æ¯ä¸º1â¶3â¶4çä¸è§å½¢æ¯ç´è§ä¸è§å½¢B.ä¸ä¸ªè§ç度æ°ä¹æ¯ä¸º3â¶4â¶5çä¸è§å½¢æ¯ç´è§ä¸è§å½¢C.ä¸è¾¹é¿åº¦ä¹æ¯ä¸º3â¶4â¶5çä¸è§å½¢æ¯ç´è§ä¸è§å½¢D.ä¸è¾¹é¿åº¦ä¹æ¯ä¸º5â¶12â¶13çä¸è§å½¢æ¯ç´è§ä¸è§å½¢çæ¡ï¼Bæ示ï¼ä¸ä¸ªè§ç度æ°ä¹æ¯ä¸æ两个ä¹åçäºå¦ä¸ä¸ªï¼å¯ä»¥å¤å®æ¯ç´è§ä¸è§å½¢ï¼å¦å¤ä¸¤è¾¹çå¹³æ¹å=第ä¸è¾¹çå¹³æ¹ï¼ä¹å¯ä»¥å¤å®æ¯ç´è§ä¸è§å½¢ï¼ä¸ä¸ªè§ç度æ°ä¹æ¯ä¸º3â¶4â¶5çä¸è§å½¢ï¼ä¸ä¸ªè§åå«æ¯45度ã60度å75度ï¼ä¸æ¯ç´è§ä¸è§å½¢.11.ä¸ä¸ªå桶åºé¢ç´å¾ä¸º24 cm,é«32 cm,å桶å
æè½å®¹ä¸çæé¿æ¨æ£ä¸ºA.20 cm B.50 cm C.40 cm D.45 cmçæ¡ï¼Cæ示ï¼æ ¹æ®å¾è¡å®çï¼æé¿æ¨æ£é¿çå¹³æ¹=242+322ï¼è§£å¾40 cm.12.ä¸èå·¥ä¸çå以50ç±³/åçé度éªèªè¡è½¦æ²¿çä¸è¥¿é©¬è·¯åä¸èµ°äº5.6å,å沿åå马路ååèµ°äº19.2åå°å®¶,åä»ç家离å
¬å¸è·ç¦»ä¸º______________ç±³.A.100 B.500 C.1 240 D.1 000çæ¡ï¼Dæ示ï¼ç±äºä¸è¥¿æ¹åä¸ååæ¹åäºç¸åç´ï¼ä¸¤æ®µè·¯ç¨ä¸å®¶ç¦»å
¬å¸è·ç¦»å½¢æç´è§ä¸è§å½¢ï¼æ ¹æ®å¾è¡å®çæ±å¾å®¶ç¦»å
¬å¸è·ç¦»= =1 000ç±³.ä¸ã解çé¢13.å¦å¾8-43ï¼å¨å边形ABCDä¸,AB=12 cm,BC=3 cm,CD=4 cm,â C=90°.å¾8-43(1)æ±BDçé¿;(2)å½AD为å¤å°æ¶,â ABD=90°?(1)çæ¡ï¼5.æ示ï¼å¨â³BDCä¸ï¼â C=90°ï¼BC=3 cmï¼CD=4 cmï¼æ ¹æ®å¾è¡å®çï¼BD2=BC2+CD2ï¼æ±å¾BD=5 cm.(2)çæ¡ï¼13.æ示ï¼æ ¹æ®å¾è¡å®ççéå®çï¼ä¸è§å½¢ä¸¤è¾¹çå¹³æ¹åçäºæè¾¹çå¹³æ¹ï¼åä¸è§å½¢æ¯ç´è§ä¸è§å½¢ï¼æ以AD=13æ¶ï¼å¯æ»¡è¶³AD2=BD2+AB2ï¼å¯è¯´æâ ABD=90°ï¼AD= =13.14.æä¸ååå°å½¢ç¶å¦å¾8-44æ示,â B=â D=90°,AB=20ç±³,BC=15ç±³,CD=7ç±³,请计ç®è¿åå°çé¢ç§¯.å¾8-44çæ¡ï¼234ç±³2.æ示ï¼è¿ç»ACï¼å°å边形åå²æ两个ä¸è§å½¢ï¼å
¶é¢ç§¯ä¸ºä¸¤ä¸ªä¸è§å½¢çé¢ç§¯ä¹åï¼æ ¹æ®å¾è¡å®çæ±åºACï¼è¿èæ±åºAD.AC= =25,AD= =24ï¼é¢ç§¯ä¸º ABÃBC+ ADÃCD=234ç±³2.15.ç²ãä¹ä¸¤è¹ä¸å11æ¶åæ¶ä»æ¸¯å£Aåºå,ç²è¹ä»¥æ¯å°æ¶20æµ·éçé度åä¸åæ¹åèªè¡,ä¹è¹ä»¥æ¯å°æ¶15æµ·éçé度åä¸åæ¹åèªè¡,æ±ä¸å1æ¶ä¸¤è¹ä¹é´çè·ç¦».å¾8-45çæ¡ï¼50æµ·é.æ示ï¼ä¸åæ¹åèªè¡ï¼ä¸åæ¹åèªè¡ï¼å夹è§ä¸º90度ï¼æ ¹æ®å¾è¡å®çï¼ç¸è·= =50.16.å·²ç¥:aãbãc为â³ABCçä¸è¾¹,ä¸æ»¡è¶³a2c2-b2c2=a4-b4,è¯å¤æâ³ABCçå½¢ç¶.解:âµa2c2-b2c2=a4-b4,â â´c2(a2-b2)=(a2+b2)(a2-b2).â¡â´c2=a2+b2.â¢â´â³ABCæ¯ç´è§ä¸è§å½¢.é®:(1)å¨ä¸è¿°è§£é¢è¿ç¨ä¸,ä»åªä¸æ¥å¼å§åºç°é误?请ååºè¯¥æ¥ç代å·: ______________;(2)é误çåå 为_________________________________________________________________;(3)æ¬é¢æ£ç¡®ç解é¢è¿ç¨:çæ¡ï¼(1)⢠(2)é¤å¼å¯è½ä¸ºé¶(3)âµa2c2-b2c2=a4-b4,â´c2(a2-b2)=(a2+b2)(a2-b2).â´a2-b2=0æc2=a2+b2.å½a2-b2=0æ¶ï¼a=bï¼å½c2=a2+b2æ¶ï¼â C=90度,â´â³ABCæ¯çè
°ä¸è§å½¢æç´è§ä¸è§å½¢.æ示ï¼(1)(2)两边é½é¤ä»¥a2-b2,èa2-b2çå¼å¯è½ä¸ºé¶ï¼ç±çå¼çåºæ¬æ§è´¨ï¼çå¼ä¸¤è¾¹é½ä¹ä»¥æé¤ä»¥åä¸ä¸ªä¸ä¸º0çæ´å¼ï¼çå¼ä»ç¶æç«.(3)æ ¹æ®çå¼çåºæ¬æ§è´¨åå¾è¡å®çï¼åæ
åµå 以讨论.17.ä¸è¾è£
满货ç©çå¡è½¦,é«2.5ç±³,宽1.6ç±³,è¦å¼è¿åé¨å½¢ç¶å¦å¾8-46æ示çæå·¥å,é®è¿è¾å¡è½¦è½å¦éè¿åé¨(åé¨ä¸æ¹ä¸ºååå½¢æ±é¨)?说æä½ ççç±.å¾8-46æ示ï¼å¦å¾ï¼ä½åé¨ç对称轴ï¼æ±åºPRçé¿ï¼åªè¦PRï¼è½¦é«2.5ï¼å°±è¯´æå¡è½¦è½éè¿åé¨.å¨Rtâ³OPQä¸ï¼ç±å¾è¡å®çå¾PQ= =0.6ç±³,â´PR=0.6+2.3=2.9ï¼2.5.â´è¿è¾å¡è½¦è½éè¿åé¨.
温馨提示:答案为网友推荐,仅供参考