#!/bin/sh first=1;echo “$first”second=1;echo –n “,$second”sum=`expr $first + $second`i=1while [ $i –le 8 ]do temp=`expr $first + $second` echo –n “,$temp” first = $second second = $temp sum=`expr $sum + $second` i=`expr $i + 1 `done
分析一下这个程序,简单分析一下就是了,谢