ç´çº¿åæ°æ¹ç¨ä¸º ï½x=2+3t/5ï¼y=4t/5ï¼
代å
¥æç©çº¿æ¹ç¨å¾ (4t/5)²=2(2+3t/5)ï¼
æ´çå¾ 8t²-15t-50=0ï¼
æ以 t1+t2=15/8ï¼t1t2=-50/8ï¼
å æ¤ x1+x2=4+9/8=41/8ï¼
y1+y2=4(t1+t2)/5=6ï¼
æ以ä¸ç¹åæ 为(41/16ï¼3)ï¼
|AB|=|t2-t1|=â[(t1+t2)²-4t1t2]
=â[(15/8)²+25]=5â73/8ã
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