用C语言程序编写1到10000奇数和

Question

用C语言程序编写1到10000奇数和

Answer 1

#include <stdio.h>
int main()
{
int i;
long sum=0;
for(i=1;i<=10000;i+=2){
sum+=i;
}
printf("1~10000的奇数和为：%d\n",sum);
return 0;
}

Answer 2

#include<stdio.h>
int main (void)
{
int n=1, sum = 0;

while(n < 10000)
{

sum = sum +n;

n = n + 2;

}

printf("10000以内的奇数和为：%d。",sum);

return 0;

}