(a1a2...a(n+1))^(1/n)
=(a1a2...an)^(1/n)*a(n+1)^(1/n)
<=[(a1+a2+...+an)/n]*a(n+1)^(1/n)
=[(a1+a2+...+a(n+1))/n-a(n+1)/n]*a(n+1)^(1/n)
=[(a1+a2+...+a(n+1))/n]*a(n+1)^(1/n)-[a(n+1)^(1+1/n)]/n
追问没看明白
追答也就是说,题目中的不等式不一定成立
追问![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/8b13632762d0f70373a19fbb04fa513d2697c542?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
那请问,画对号的地方,是怎么过来的
追答画√的地方没有问题,根号内只有n项