1.
å 为f(x)=2^x-a/2^x+1为å¥å½æ°,
æ以
f(0)=(1-a)/(1+1)=0
1-a=0
a=1
2.
f(x)=(2^x-1)/(2^x+1)
=(2^x+1-2)/(2^x+1)
=1-2/(2^x+1)
å 为
2^xæ¯å¢å½æ°,æ以
2/(2^x+1)æ¯åå½æ°,ä»è
-2/(2^x+1)æ¯å¢å½æ°,å³
f(x)=(2^x-1)/(2^x+1)æ¯å¢å½æ°.
3.
å 为f(1)=(2-1)/(2+1)=1/3
æ以
f(x^2-2x)<1/3=f(1)
å½æ°æ¯å¢å½æ°,æ以
x^2-2x<1
x^2-2x+1<2
(x-1)^2<2
1-â2<x<1+â2
温馨提示:答案为网友推荐,仅供参考