java中如何用正则表达式判断一个字符串中是否包含0-9的数字？

Question

如题所述

Answer 1

// 判断一个字符串是否都为数字
public boolean isDigit(String strNum) {
return strNum.matches("[0-9]{1,}");
}

// 判断一个字符串是否都为数字
public boolean isDigit(String strNum) {
Pattern pattern = Pattern.compile("[0-9]{1,}");
Matcher matcher = pattern.matcher((CharSequence) strNum);
return matcher.matches();
}

//截取数字
public String getNumbers(String content) {
Pattern pattern = Pattern.compile("\\d+");
Matcher matcher = pattern.matcher(content);
while (matcher.find()) {
return matcher.group(0);
}
return "";
}

// 截取非数字
public String splitNotNumber(String content) {
Pattern pattern = Pattern.compile("\\D+");
Matcher matcher = pattern.matcher(content);
while (matcher.find()) {
return matcher.group(0);
}
return "";
}
// 判断一个字符串是否含有数字
public boolean hasDigit(String content) {
boolean flag = false;
Pattern p = Pattern.compile(".*\\d+.*");
Matcher m = p.matcher(content);
if (m.matches())
flag = true;
return flag;
}