若(2x^2+ax-y+b)-(2bx-3x+5y-1)的值与字母x的取值无关,求ab的值.

Question

如题所述

Answer 1

(2x^2 - 2bx^2) + (ax + 3x) + (-y - 5y + 1) = (2 - 2b)x^2 + (a+3)x + (-6y+1) 因为 取值和x无关所以 2 - 2b = 0,