过7游戏用python怎么写

Question

如题所述

Answer 1

代码为：

import re

def xiny(x, y):
    return bool(re.findall(x, y))

i = 1
while i <= 100:
    if i % 7 == 0 or xiny("7", str(i)) == True:
        print("过", end=",")
    else:
        print(i, end=",")
    i = i + 1

输出结果：

1,2,3,4,5,6,过,8,9,10,11,12,13,过,15,16,过,18,19,20,过,22,23,24,25,26,过,过,29,30,31,32,33,34,过,36,过,38,39,40,41,过,43,44,45,46,过,48,过,50,51,52,53,54,55,过,过,58,59,60,61,62,过,64,65,66,过,68,69,过,过,过,过,过,过,过,过,过,过,80,81,82,83,过,85,86,过,88,89,90,过,92,93,94,95,96,过,过,99,100,

Answer 2

#输入任意的一个数字的范围之内，所有的7的倍数和包含有数字7的数字
i = 1
datemax = input("pls input a value range")
data = int(datemax)
while (i <= data):
b = i % 7
e = str(i)
if (b == 0):
print("7的倍数")
elif e.find("7") != -1 :
print ("含有7")
else :
print (i)
i += 1

Answer 3

哥虽然不帅但不是你轻而易举就
有些事你把它藏到心里也
当流血的夜晚得到包扎

Answer 4

原来郑和船队的高级武职人
雪花并不大像些小粉虱路灯

Answer 5

拉着你的手和你去天涯海角
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