正弦函数的泰勒展开式可以通过数学归纳法和三角函数的运算性质得到。
首先,我们知道 (x-π/2)^0 = 1,因此正弦函数的泰勒展开式必须以x^0的系数开始。接下来,我们考虑将正弦函数进行泰勒展开,得到
sin(x) = a_0 + a_1*(x-π/2) + a_2*(x-π/2)^2 + a_3*(x-π/2)^3 + ...
其中a_n是正弦函数的泰勒系数。
根据正弦函数的定义,我们有
sin(x) = {sin(x)}' = cos(x){cos(x)}' = -sin(x){sin(x)}'' = -cos(x)*{cos(x)}'' = ...
因此,我们可以得到
a_0 = sin(π/2) = 1
a_1 = -cos(π/2) = 0
a_2 = -sin(π/2) = -1
a_3 = cos(π/2) = 0
...
因此,正弦函数的泰勒展开式为
sin(x) = 1 - (x-π/2) + (x-π/2)^2/3 - (x-π/2)^3/45 + ...