怎么查看当前数据库的所有对象，包括表，视图，存储过程等。。

Question

谢谢
mssql 2000.

Answer 1

use DB
go
select * from sysobjects

xtype
char(2)
物件类型。它可以是下列物件类型之一：

C = CHECK 条件约束

D = 预设值或 DEFAULT 条件约束

F = FOREIGN KEY 条件约束

L = 记录

FN = 纯量函数

IF = 内嵌资料表函数

P = 预存程序

PK = PRIMARY KEY 条件约束 (类型是 K)

RF = 复写筛选预存程序

S = 系统资料表

TF = 资料表函数

TR = 触发程序

U = 使用者资料表

UQ = UNIQUE 条件约束 (类型是 K)

V = 检视

X = 扩充预存程序

Answer 2

最好是下个mysql的工具，不但可以看你上面提到的内容，还可以将数据导出成excel或txt 数据 推荐在360上有个MySQL Tools for 5.0 比较好用

Answer 3

SELECT

对象名=case when a.colorder=1 then d.name else '' end,

说明=case when a.colorder=1 then isnull(f.value,'') else '' end,

序号=a.colorder,
字段或参数名=a.name,
标识=case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,

主键=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and name in (

SELECT name FROM sysindexes WHERE indid in(

SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid

))) then '√' else '' end,

类型=b.name,

占用字节数=a.length,

长度=COLUMNPROPERTY(a.id,a.name,'PRECISION'),

小数位数=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),

允许空=case when a.isnullable=1 then '√'else '' end,

默认值=isnull(e.text,''),

字段说明=isnull(g.[value],'')

FROM syscolumns a

left join systypes b on a.xusertype=b.xusertype

inner join sysobjects d on a.id=d.id and d.name<>'dtproperties'

left join syscomments e on a.cdefault=e.id

left join sysproperties g on a.id=g.id and a.colid=g.smallid

left join sysproperties f on d.id=f.id and f.smallid=0

order by a.id,a.colorder