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1)通过外加电源法求等效电阻 Ro;
R = R1//R2;那么有 (i + 2i)* R = U;
Ro = U/i = 3R;
2)
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求ab短路短路 Isc;
Us/R2 + i + 2i = 0;
i = U2/3R2,则 Isc = -i;
所以ab端的诺顿等效电路为:电流源 Isc 和 Ro 的并联;
或者其戴维南等效电路为:电压源 Uoc=Isc*Ro 和 Ro 的串联;
而 RL = Ro 时获得最大功率;
追问请教一下
受控源你是如何处理的?
追答受控源,控制变量都一直保留,没处理啊
追问为什么你第二个R1就没管了呢?
追答说的是ab端短路了也就没R1什么事了