解ï¼1ãSæå¼æ¶ã
KCLï¼I1+I3=I2ã
KVLï¼I1R+I2R+E=Eï¼E+I2R+I3R=Eã
I1=-I2ï¼I3=-I2ã解å¾ï¼I1=I2=I3=0ã
2ãSéåæ¶ï¼
I1R=Eï¼I1=E/R=12/3=4ï¼Aï¼ï¼
E+I2R=0ï¼I2=-E/R=-12/3=-4ï¼Aï¼ï¼
I3R=Eï¼I3=E/R=12/3=4ï¼Aï¼ã
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