你好,刚刚问的问题 都不用看了 帮忙看下这个?
var a = [ {
"id" : "0000",
"name" : "ROOT",
"age" : 1,
"pjz" : 2,
"children" : [ {
"id" : "1000",
"name" : "1年",
"age" : 2,
"pjz" : 3,
"children" : [ {
"id" : "1001",
"name" : "1年1",
"age" : 3,
"pjz" : 5
} ]
}, {
"id" : "2000",
"name" : "2年",
"age" : 4,
"pjz" : 8
} ]
} ];
var b = [ {"field" : "age","type" : "sum"},{"field" : "pjz","type" : "default"},{"field" : "id","type" : "default"}];
由a,b得到c,若a中节点的值在b中类型为sum的进行求和
var c = [ {
"id" : "0000",
"name" : "ROOT",
"age" : 6,为1+2+3(本身的值加上子节点age的值)
"pjz" : 2,
"children" : [ {
"id" : "1000",
"name" : "1年",
"age" : 5,为2+3(本身的值加上子节点age的值)
"pjz" : 3,
"children" : [ {
"id" : "1001",
"name" : "1年1",
"age" : 3,为3(本身的值加上子节点age的值)
"pjz" : 5
} ]
}, {
"id" : "2000",
"name" : "2年",
"age" : 4,为4(本身的值加上子节点age的值)
"pjz" : 8
} ]
} ];
不好意思 请问如果"age"的值为字符串 在代码哪边转换成数字类型 帮忙看下哈 没找到
追答如果你的age是字符串类型
那麽
var Sum = function(List,Field)