第1个回答 2022-06-17
因式分解
分解因式
反过来
（t-2)(t-2)(t+4)
=(tt-4t+4)(t+4）
=ttt-4tt+4t+4tt-16t+16
=ttt-12t+16
分解因式
反过来
（t-2)(t-2)(t+4)
=(tt-4t+4)(t+4）
=ttt-4tt+4t+4tt-16t+16
=ttt-12t+16
第2个回答 2022-06-17
t³-12t+16<0,则有
t³-4t²+4t²+4t-4t-12t+16<0
t³-4t²+4t+4t²-16t+16<0
t(t²-4t+4)+4(t²-4t+4)<0
t(t-2)²+4(t-2)²<0
(t-2)²(t+4)<0
t³-4t²+4t²+4t-4t-12t+16<0
t³-4t²+4t+4t²-16t+16<0
t(t²-4t+4)+4(t²-4t+4)<0
t(t-2)²+4(t-2)²<0
(t-2)²(t+4)<0
第3个回答 2022-06-17
t³-12t+16
=t³-8-12t+24
=(t³-8)-12(t-2)
=(t-2)(t²+2t+4)-12(t-2)
=(t-2)(t²+2t-8)
=(t-2)[(t-2)(t+4)]
=(t-2)²(t+4)本回答被提问者采纳
=t³-8-12t+24
=(t³-8)-12(t-2)
=(t-2)(t²+2t+4)-12(t-2)
=(t-2)(t²+2t-8)
=(t-2)[(t-2)(t+4)]
=(t-2)²(t+4)本回答被提问者采纳