1ãå¨æéå±ç¦»ååå ççµæååºä½ç³»ä¸ï¼å å
¥æ²æ·åæ¶ï¼
å¦ææ¯æ°§åå离åæµåº¦éä½ï¼è¯¥çµæççµæçµå¿å¼å°éä½
å¦ææ¯è¿åå离åæµåº¦éä½ï¼è¯¥çµæççµæçµå¿å¼å°åé«
å¯ä»¥éè¿è½æ¯ç¹æ¹ç¨
E=E0 +0.0591/n*lg[æ°§åå]/[è¿åå]
2ãå·²ç¥çµæååºO2ï¼4H+ï¼4eï¼2H20çæ åçµæçµå¿ä¸º1.229Vï¼
è¦æ±ï¼çµæååºO2+2H2O+4e=4OH-çæ åçµæçµå¿ï¼è¿æ¶pï¼O2ï¼=100KPa
cï¼OH-ï¼=1mol/L cï¼H+ï¼=10^-14
O2+2H2O+4e= 4OH-
100KPa 1mol/L
ä¸å¼çæ¬è´¨ä¸º O2 ï¼ 4H+ ï¼4eï¼2H2O
100KPa 10^-14mol/L
å æ¤E0(O2/OH-)=E(O2/H2O)=E0(O2/H2O)+0.0591/4*lg {(p(O2)/P0)*[c(H+)/C0]^4 }
=1.229V +0.0591 V/4 *lg(10^-14)^4
=0.401V
温馨提示:答案为网友推荐,仅供参考