1)f(x)=x^3+x^2+ax+b
f'(x)=3x^2+2x+a
=3x^2+2x-1
=(x+1)(3x-1)
x1=-1 x2=1/3
(-â,-1)(1/3,+â)为å¢åºé´
(-1,1/3)为ååºé´
2ï¼è®¾g(x)=x^3+x^2+ax+b-ax=x^3+x^2+b
g'(x)=3x^2+2x
=x(3x+2)
x1=0 x2=-2/3
(-â,-2/3)(0,+â)为å¢åºé´
(-2/3,0)为ååºé´
æ以个g(-2/3)*g(0)ï¼0
bâ(-4/27,0)
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