sin(x+y)的导数

Question

如题所述

Answer 1

求导计算过程如下：
y=sin(x+y)
两边求导：
y'=cos(x+y)*(1+y')
y'=cos(x+y)+y'cos(x+y)
y'[1-cos(x+y)]=cos(x+y)
y'=cos(x+y)/[1-cos(x+y)].