答案是 3 我用程序算的: program tt; var time:longint; n:longint; begin readln(n); while time<2012 do begin inc(time); if odd(n) then inc(n,7) else n:=n>>1; end; writeln(n); end.
第2个回答 2012-06-05
QBasic: for i=1 to 2012 input "",n if n mod 2=0 then p=n/2 else p=n+7 next i print "2012 ci jie ge shi :";p end