1ã20mL0.2mol/Lç氨水pHå¼çäºå¤å°ï¼pOH=1/2(pKb+p0.2)=1/2(4.75+0.699)=2.73
pH=14.00-2.73=11.27
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åæ40mL0.05mol/Lde NH3å0.05mol/LçNH4Ac,ææç¼å²æº¶æ¶²
pOH=pKb=4.75ï¼pH=14.00-4.75=9.25
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