若不完全燃烧则(x+
)>
=5,70mL为一定含有CO、可能含有CO
2,根据碳元素守恒x=3.5,不合题意,故该烃完全燃烧,
该烃的分子式为C
xH
y,烃燃烧生成液态水,若烃完全燃烧,则:
C
xH
y+(x+
)O
2→xCO
2+
H
2O(l) 体积减小
1 1+
20mL 20mL+100mL-70mL=50mL
所以,1:(1+
)=20mL:50mL,解得y=6,
完全燃烧,则(x+
)≤5,所以x≤3.5,故x=2或3,故该烃为C
2H
6 或C
3H
6 ,其可能结构简式为 CH
3─CH
3 、CH
2=CH─CH
3或
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f9198618367adab4532fdcf288d4b31c8601e480?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
,
答:该烃为C
2H
6 或C
3H
6 ; 其可能结构简式为CH
3─CH
3 、CH
2=CH─CH
3或
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/f9198618367adab4532fdcf288d4b31c8601e480?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
.