解ï¼ï¼1ï¼b+c=(sinx-cosx,,sinx-3cosx)
â´f(X)=sin^2x-sinxcosx-sinxcosx+3cos^2x=2+æ ¹å·2sin(-2x+Ï/4)
â´2-æ ¹å·2<=f(x)<=2+æ ¹å·2â´æå°å¼ä¸º2-æ ¹å·2ï¼æå°æ£å¨æï¼2Ï/|-2|=Ï
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³äºåç¹å¯¹ç§°ï¼â´-2(x+a)+Ï/4=-2x â´2a=Ï/4â´a=Ï/8æ
é¿åº¦æå°çd=(-Ï/8,-2ï¼
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