求下列不定积分

Question

如题所述

Answer 1

换元x=cosu，u=arccosx
=∫10^u/sinudcosu
=-10^u/ln10+C追答

(18)=2∫sec√td√t=2ln|sec√t+tan√t|+C

(19)=1/10∫1/√(2-x^20)dx^10
=(1/10)arcsin(x^10/√2)+C